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		Haruki's Lemma
		This truly beautiful lemma is due 
		to Hiroshi Haruki. It leads to the 
		easiest proof of the
		
		Butterfly and
		
		Two Butterflies Theorems. You can see the proof on a great website 
		of 
		Alexander Bogomolny.
 
		Lemma ( Haruki ) Given two 
		nonintersecting chords AB and CD in a circle and a 
		variable point P 
		on the arc AB remote from points C and D, define 
		points E and F as intersections of chords PC and 
		AB, PD and AB respectively. Then, the value of the 
		fraction AE · BF / EF does not depend on the position of a point
		P. 
		 
		    This problem came about when I was 
		giving geometry lectures to students at the TTST 2006 (Transcarpathian 
		Team Selection Test) for the Ukrainian Math Olympiad. The first proof of 
		Haruki's Lemma that I've found was full of horrible trigonometry. For 
		the second proof I have decided to try out my skills in the application 
		of complex numbers to geometry. This proof was REALLY LONG !!! However, 
		it gave me an idea of what to go for and the third proof, that was based 
		on Hiroshi Haruki's original proof of the lemma, was short and, what's 
		more important, fully synthetic - no ugly Trig or long complex 
		numbers!!!Feeling confident, I've decided to study the situation with 
		the help of trilinear coordinates, leading to the fourth proof. However, 
		using trilinear coordinates was not the end of the story. However, at 
		the request of the Editor-in-Chief, I had to redo the whole thing by 
		using the barycentric coordinates. Well, you can 
		see what this led to if you check out 
		my article over at
		Forum 
		Geometricorum.
 
		    One of my results states that the ratio
		AE · BF / EF  actually equals ... *drum 
		roll* ... hover your mouse
		
		here to find out. Isn't that sweet? What's even more sweet is the 
		fact that this equality holds even when chords AB and 
		CD are intersecting and point P is an arbitrary point on the 
		circle distinct from A and B !!! 
		    Well, if you are interested, just 
		read my article: "Haruki's 
		Lemma and a Related Locus Problem". 
		    It turns out that the results 
		described in that article can be extended to conics, and you can read 
		about it here: 
		
		"Haruki's Lemma for Conics".I hope there are still more interesting results that use 
		Haruki's Lemma.
 
		 AC · BD / CD 
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