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Haruki's Lemma
Lemma ( Haruki ) Given two nonintersecting chords AB and CD in a circle and a variable point P on the arc AB remote from points C and D, define points E and F as intersections of chords PC and AB, PD and AB respectively. Then, the value of the fraction AE · BF / EF does not depend on the position of a point P.
This problem came about when I was
giving geometry lectures to students at the TTST 2006 (Transcarpathian
Team Selection Test) for the Ukrainian Math Olympiad. The first proof of
Haruki's Lemma that I've found was full of horrible trigonometry. For
the second proof I have decided to try out my skills in the application
of complex numbers to geometry. This proof was REALLY LONG !!! However,
it gave me an idea of what to go for and the third proof, that was based
on Hiroshi Haruki's original proof of the lemma, was short and, what's
more important, fully synthetic - no ugly Trig or long complex
numbers!!! One of my results states that the ratio AE · BF / EF actually equals ... *drum roll* ... hover your mouse here to find out. Isn't that sweet? What's even more sweet is the fact that this equality holds even when chords AB and CD are intersecting and point P is an arbitrary point on the circle distinct from A and B !!! Well, if you are interested, just read my article: "Haruki's Lemma and a Related Locus Problem".
It turns out that the results
described in that article can be extended to conics, and you can read
about it here:
"Haruki's Lemma for Conics". |
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